7/23/2019 0024.pdf

1/2

AAAA11111111 10 ( . 11)10 ( . 11)10 ( . 11)10 ( . 11) E 1E 1E 1E 1

2.2.2.2. ????

2 3 4

C

2 .

2= 23= 6 = 2+ 2.24= 12 = 3+ 3.25= 20 = 4+ 4.2...= 1+ (1).2

1 = 2.(1) ,

.

= ( 1) + (1 2) + ...+ (4 3) + (3 2) + 2

= 2.(1) + 2.(2) + ... + 6 + 4 + 2

=() .()

+ 2

=().()

+ 2

=().()

+ 2

= 2 2 + 2 + 2

= 2

7/23/2019 0024.pdf

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A11A11A11A11 10101010 ( . 11)( . 11)( . 11)( . 11) E 2E 2E 2E 2

2.2.2.2. ????

C 2 2:

C =

!

!()!=

.().()!

!()! =

.()

C ,

:

= 2.C= 2..()

= .(1) = 2