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7/23/2019 ex02-01_pt
http://slidepdf.com/reader/full/ex02-01pt 1/4
x + y = 1
x + y = 1
x2i
x2n+1i−1
x2 − 1
x + 1 = x − 1
n
n
4√ x2 =
|x|
± =,≤,≥,≡,→
α,β,γ
Π,Σ,Λ
X
f → Y
7/23/2019 ex02-01_pt
http://slidepdf.com/reader/full/ex02-01pt 2/4
1x
3√ x2 + 1
x ∈ [0, 1) :
x + 1
x
−1 < 0
2
1 +
1 + 1
5
22
+ 5
x2
x + 1
x=1
= 1
2
x · y
a0 + a1 + · · · + an = (a0+an)n
2
{x0, x1, x2, . . . , xn, . . .}
{x ∈ [0,∞) | cos(x)| < 1
2}
7/23/2019 ex02-01_pt
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∞n=1
1
n = ∞
f (x) = limx→a
f (x) − f (a)
x− a
inf n>0
1
n
= 0
n! =n
i=1
i
baf (x)dx = F (b) − F (a)
I
f = baf (x)dx
∞
n=0 xi
n 1 + 1 + · · · + 1 = n
k + k + · · · + k n
= k
7/23/2019 ex02-01_pt
http://slidepdf.com/reader/full/ex02-01pt 4/4
126
126
Γ kij
Γkij