7/24/2019 Exerccios resolvidos sobre lei de kirchhoff

1/8

RESOLUES DOS EXERCCIOS ATIVIDADE ESTRUTURADA

1)

10+8=I2I2=18 A

I3+9=18I

3=189I

3=9 A

8+I1=9I1=98 I1=1 A

2)

+810+V2=0V

2=2V

+9+V38=0V

3=1V

Fazendo a analise do s!e" n#$ %e&os'

E4E2=1 E4=E21

7/24/2019 Exerccios resolvidos sobre lei de kirchhoff

2/8

E3E4=9

E3E

2=8

E1E

2=10 E1=E2+10

E1E

3=2

E1E

4=V

1 A

Isolando os %e"&os ne(ess"ios e s*s%i%indo na e+a,-oA$ %e&os'

( E

2+10(E21 )=V1 V1=E2+10E2+1 V1=11V

.)

+5+6 I+8I8+11I12+10I+15 I=0

50I15=0

I=15

50I=0,3 A

/)

7/24/2019 Exerccios resolvidos sobre lei de kirchhoff

3/8

+30+0,54+1440+R34=0

4 R310+6=0

R3=4

4R3=1

0)

# ' I1+I3=I2

I1+4=I2 I2=4+I1 A

3AL4A A' +100,3I20,5I112=0

0,3I20,5 I1=2 5

S*s%i%indo Ae& 5'

0,3(4+I1)0,5 I1=2

1,20,3I10,5I

1=2

I1= 3,2

0,8 I1=4 A (Sentido contrrio ao adotado)

Logo, podemos concluir queI2=0 A

, poisI2=44=0

3AL4A 5' +14+R34+0,3I210=0

4+4 R3+0,3010=0

x

B

i

i1A

7/24/2019 Exerccios resolvidos sobre lei de kirchhoff

4/8

4 R36=0

R3=6

4R3=1,5

6)

3AL4A A' 3+50,2+R2I2=0

R2I

22=0R

2I

2=2 A

3AL4A 5' R2I2+55I3=0

R2I25I3=5R2I2=5+5 I3 5

S*s%i%indoAe& 5' 2=5+5I3

5I3=52I3=3

5 I3=0,6 A

So&a%#"ia das (o""en%es no n# X' I1+I3=I2

0,2+0,6=I2I

2=0,8 A

S*s%i%indo o 7alo" en(on%"ado na e+a,-o A' R2I2=2

R20,8=2

X

B

A

7/24/2019 Exerccios resolvidos sobre lei de kirchhoff

5/8

R2= 2

0,8R2=2,5

8)

# X' I3+I2=I1 A

3AL4A A' 10012I1+80+3I240=0

12I1+3I

2=60 5

S*s%i%indo Ae& 5'

12(I3+I2)+3 I2=60

15I2+12I

3=60 C

3AL4A 5' 403I2+3I3102+2I3=0

3 I2+5I

3=62 D

15I2+12I

3=60 15I2+12I3=60

3 I2+5I3=62 (*5) 15 I2+25I3=310

37 I3=370

I3=

370

37I

3=10 A

S*s%i%indo o 7alo" en(on%"ado na e+a,-o D' 3 I2+5I3=62

B

7/24/2019 Exerccios resolvidos sobre lei de kirchhoff

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3 I2+510=62

I2=62503

I2=4 A 9Sen%ido (on%""io ao ado%ado)

S*s%i%indo os 7alo"es das (o""en%es en(on%"adas na e+a,-o A'I3+I2=I1

I1=104I

1=6 A

:)

3AL4A A' 90+10I1=0

I1=90

10I

1=9 A

3AL4A 5' 109+25I2+30+15I2=0

40 I2=60

I2=60

40

I2=1,5 A

;)

B

A

BA

7/24/2019 Exerccios resolvidos sobre lei de kirchhoff

7/8

3AL4A A' 100+20I1=0

I1=100

20I1=5 A

3AL4A 5'

25I2200=0

I2=200

25 I2=8 A

I=I1+I2=58I=3 A 9Sen%ido (on%""io ao ado%ado)

1

7/24/2019 Exerccios resolvidos sobre lei de kirchhoff

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11)

3AL4A A'

20+10103I1+5=0

I1

= 15

10000 I

1

=1,5103 A

3AL4A 5'

5+2520103I3=0

I3= 2020000

I3=1103A

=OTECIA E3 R1 '

P=VI=201103=20103W=20mW

=OTECIA E3 R2 '

P=VI=151,5103=22,5103W=22,5mW

12)

"!

"2

"1

B

A