ESCOLA SESI “FERNANDO ARRAES DE ALMEIDA” – LEME/SP

AVALIAÇÃO EDUCAÇÃO BÁSICA NOTA

ENSINO MÉDIO

Disciplina FÍSICA SÉRIE / ANO:

ALUNO(A): Nº

PROFESSOR(A): Duane Damaceno DATA: 26/10/2018

OBJETIVO: Questionar, refletir e calcular questões do cotidiano envolvendo as três leis de Newton

ATIVIDADE- RECUPERAÇÃO CONTÍNUA

ATIVIDADE AVALIATIVA

X

ATIVIDADE- DIVERSIFICADA

ATIVIDADE- DIFERENCIADA

1-(1,0) Vimos em sala o argumento de um líder religioso sobre a Terra estar parada. Este argumento dizia que, se a Terra se movesse, um helicóptero poderia simplesmente subir, esperar que a Terra girasse e pousar sem ter se deslocado para frente e mesmo assim chegar ao seu destino. Qual é o erro deste argumento? O erro é, como o avião está na Terra, ele permanece girando junto com a Terra. Seu giro é solidário. 2-(0,5) Toda vez que andamos, estamos fazendo uso de uma lei de Newton. Qual é esta lei e descreva como ela permita que você anda. Ação e reação. Quando andamos, empurramos a Terra para trás e ela nos empurra para frente. 3-(1,0) Muitos soldados, quando em batalha, devem saltar dos caminhões ainda em movimento, para que o caminhão não seja alvo de tiros. Porém, este salto dos soldados pode gerar várias quedas dos mesmos. Por que estás quedas podem acontecer? Explique baseando-se em uma das leis de Newton. Pela lei da inércia, o soldado, mesmo após saltar do caminhão, continua em movimento. Como suas pernas estão paradas, ele não está “preparado” para se deslocar e então cai. 4-(1,0) Quando pulamos, estamos, na verdade, empurrando a Terra para baixo e ela nos empurra para cima. Desta forma nós conseguimos sair do chão. Porém, não notamos movimento da Terra. Isto quer dizer que a força que fazemos na Terra é menor do que a força que a Terra faz em nós? Justifique. Não! Pela lei de ação e reação as forças são iguais. O que difere é que a massa da Terra é muito maior que a nossa e, portanto, sua aceleração é bem menor. 5-(1,0) Um tijolo de 5 kg está em um plano inclinado que faz 30º com a horizontal. Admitindo que o coeficiente de atrito estático seja de 0,8 e o de atrito cinético seja de 0,6, responda.

a) O corpo irá, naturalmente, escorregar pelo plano? Devemos comparar Px com Fe

Como Fe > Px, o corpo não se movimentará.

b) Se sua resposta anterior foi sim, qual o valor da aceleração que ele adquire? Se foi não, quanto vale a força de atrito que o mantém parado? A força de atrito estática sempre vale a mesma quantidade que a força que é aplicada no corpo (Px). Portanto, Fe = 25 N

Px = P.sen(30o)Px = 50.0, 5Px = 25N

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FE = N.µe

FE = Py.0, 8FE = P.cos(30o).0, 8

FE = 50.

p3

2.0, 8

FE = 20p3

FE ⇡ 20.1, 7FE ⇡ 34N

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6-(1,0) Um corpo de 20 kg sofre a ação de uma força de 100 N. Qual será a aceleração deste corpo?

7-(1,0) Um corpo de 100 kg está encostado em outro corpo de 70 kg. Se o corpo de 100 kg recebe uma força de 85 N, qual é a aceleração que eles adquirem? Qual o valor da força de contato?

Se o corpo de 100 kg que recebe a força, o corpo de 70 kg irá receber apenas a força de contato. Portanto, podemos utilizá-lo para descobrir a força de contato.

8-(1,0) Um corpo recebe uma força de 200 N e isto gera uma aceleração de 5 m/s2. Qual o valor da massa deste corpo?

10-(1,0) Dois corpos, um de 40 kg e outro de 80 kg, estão juntos e a força é aplicada no corpo de 40 kg. Se a força aplicada é de 60 N, qual é a aceleração que estes corpos adquirem?

11-(0,5) Dois corpos, um de 40 kg e outro de 60 kg, sofrem a ação de uma força de 200 N. A força de contato entre eles é de 80 N. Em qual dos corpos foi aplicada a força? Neste exercício é preciso calcular a aceleração primeiro. Após isto, montamos o esquema dos corpos e vemos, em qual deles, a força de 80 N pode ser a força de contato. Vale a pena lembrar que, o corpo que recebe a força aplicada, possui, além da força aplicada, a força de contato. O outro corpo, recebe apenas a força de contato.

FR = m.a100 = 20.a100

20= a

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FR = m.a85 = 170.a85

170= a

0, 5m/s2 = a<latexit sha1_base64="/ZOONP9BqinO9oEEEuHiRUHJkC0=">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</latexit><latexit sha1_base64="bb5W6P/uN0c6PyUeFFUBscdd9Z0=">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</latexit><latexit sha1_base64="bb5W6P/uN0c6PyUeFFUBscdd9Z0=">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</latexit><latexit sha1_base64="u24+sslP+mo+Fq9xdfDmOVU0nGU=">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</latexit>

F = m.aF = 70.0, 5F = 35N

<latexit sha1_base64="IJQcfbByOWOnzbX4YF7p+WAU+Mk=">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</latexit><latexit sha1_base64="1rGvxA1zquMGb6+/U98voUj8Nkc=">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</latexit><latexit sha1_base64="1rGvxA1zquMGb6+/U98voUj8Nkc=">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</latexit><latexit sha1_base64="UjHZhPjXW01/UrI9iJACCSS6lag=">AAACB3icdVDLSgMxFM34rONr1KUgwSJ0IcNMdWy7KBQEcSUV7APaUjJp2oYmM0OSEUrpzo2/4saFIm79BXf+jZlpBRU9cOHknHvJvcePGJXKcT6MhcWl5ZXVzJq5vrG5tW3t7NZlGAtMajhkoWj6SBJGA1JTVDHSjARB3Gek4Y/OE79xS4SkYXCjxhHpcDQIaJ9ipLTUtQ4uYBlyG8F220xowbGdYy99lU+8q66VdexS0SudFqF2UiQkf1byXOjOlSyYo9q13tu9EMecBAozJGXLdSLVmSChKGZkarZjSSKER2hAWpoGiBPZmaR3TOGRVnqwHwpdgYKp+n1igriUY+7rTo7UUP72EvEvrxWrfrEzoUEUKxLg2Uf9mEEVwiQU2KOCYMXGmiAsqN4V4iESCCsdnalD+LoU/k/qedt1bPfayVZy8zgyYB8cghxwQQFUwCWoghrA4A48gCfwbNwbj8aL8TprXTDmM3vgB4y3T6Y/lKA=</latexit>

FR = m.a200 = m.5200

5= m

40kg = m<latexit sha1_base64="3nH8kzil+/pqwR2YRxW6Jzqhh/s=">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</latexit><latexit sha1_base64="si3lqsIb3MFOcspw3n34i7hOKFc=">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</latexit><latexit sha1_base64="si3lqsIb3MFOcspw3n34i7hOKFc=">AAACH3icdZDNSgMxEMezflu/qh69BEXoac2WtraHQkEQjyq2VrqlZNNsDU12lyQrlKWP4c2Lr+LFgyLirWcfwQfQbKugogOB//xmhsn8vYgzpREaWVPTM7Nz8wuLmaXlldW17PpGQ4WxJLROQh7KpocV5Sygdc00p81IUiw8Ts+9/kFaP7+iUrEwONODiLYF7gXMZwRrgzrZ0mHntCpsDF03k0cIVqGwi2ni+hKTxKBhUhymOIUFBPu9NOlkd5BdKRcrhTJENhpHKvKlStGBzifZqcHrvde3i/fjTvbF7YYkFjTQhGOlWg6KdDvBUjPC6TDjxopGmPRxj7aMDLCgqp2M7xvCXUO60A+leYGGY/p9IsFCqYHwTKfA+lL9rqXwr1or1n65nbAgijUNyGSRH3OoQ5iaBbtMUqL5wAhMJDN/heQSG2O0sTRjTPi6FP4vGnnbQbZzYtzIgUksgC2wDXLAAfugBo7AMagDAm7AHXgAj9atdW89Wc+T1inrc2YT/Ahr9AERp6HL</latexit><latexit sha1_base64="mnsrp+8A0+i25u+5QiBApqHUxhY=">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</latexit>

FR = m.a60 = 100.a60

100= a

0, 6m/s2 = a<latexit sha1_base64="U3ps11vvawsWhSCLiRkXgFKc4Lg=">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</latexit><latexit sha1_base64="b6Oh0oY+JG4y2rq7ecE+ac7Fu6U=">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</latexit><latexit sha1_base64="b6Oh0oY+JG4y2rq7ecE+ac7Fu6U=">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</latexit><latexit sha1_base64="euoFGCsLN5NBEz19nZQ6fSMH4V4=">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</latexit>

Se o corpo que recebe a força for o corpo de 40 kg, o corpo de 60 kg receberá apenas a força de contato. Então ela será sua força resultante.

Perceba que a força de contato deu 120 N. Portanto, não pode ser no corpo de 60 kg. Se a força for aplicada no corpo de 60kg, o corpo de 40 kg só recebe a força de contato:

Desta forma, a força de contato “bate” com o valor do enunciado. Portanto, quem recebeu a força foi o corpo de 60 kg. 12-(1,0) Um plano inclinado que faz um ângulo tal que seu seno valha 0,8 e seu cosseno valha 0,6 possui uma massa de 20 kg apoiada nele. Qual será a força resultante e a aceleração neste corpo, caso não exista atrito?

FR = m.a200 = 100.aa = 2m/s2

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FR = m.aF = 60.2F = 120N

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FR = m.aF = 40.2F = 80N

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FR = m.aPx = 20.aP.sen(↵) = 20.a200.0, 8 = 20.a160 = 20.a160

20= a

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