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CH3Br, 270110 HBr spectra Agust, heima,... Jan10/CH3Br18750_19250-Hbr-sim-050110km-270110ak.pxp Agust, www, ...Jan10/PPT-270110ak.ppt. Thus for example:. 152926.9. C + +H 2 +HBr+e -. 150k. C**( 1 D 2 )+H 2 +HBr. 147506.154. 130k. Analyse HBr REMPI in neighbourhood of 75200 cm -1. - PowerPoint PPT Presentation
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CH3Br, 270110
HBr spectra
Agust, heima,... Jan10/CH3Br18750_19250-Hbr-sim-050110km-270110ak.pxpAgust, www, ...Jan10/PPT-270110ak.ppt
75204.554 cm-1
37602.277
CH3Br10k
40k
70k 72301.6
CH3Br* C*(1D2)+H2+HBr
0 12
C**(1D2)+H2+HBr
J’’
147506.154
130k
150k C++H2+HBr+e-152926.9Thus for example:
Analyse HBr REMPIin neighbourhood of75200 cm-1
HBr REMPI spectra:1) See our paper: JCP, 112(24), 10811, (2000):
Main reference for HBr (2+1)REMPI is:R. Callaghan & RJ Gordon, JCP, 93(7), 4624, (1990):
http://www3.hi.is/~agust/rannsoknir/papers/jcp93-4624-90.pdf
Look for H79Br+ and/or H81Br+ ion signals vs 2hv in that region
1.0
0.5
0.0
-0.5
75.575.475.375.2x10
3
Simulation (from KM):
-22
-20
-18
-16
-14
-12
-10
-8
7654321
-0.6
-0.4
-0.2
0.0
37.70x103
37.6837.6637.6437.622xh[cm
-1]
Experimental
Calculated
Coefficient values ± one standard deviation a = -4.8333 ± 0.312 b = -1.35 ± 0.144
agust,heima,...Jan10/CH3Br18750_19250-Hbr-sim-050110km-270110ak.pxp
7 5
DJ
DJ=
Dnjucm-1
b = -1.35 ± 0.144
Assuming b =2(B´-B´´) = -1.35 =>
(B´-B´´) = -0.675 =>B´= 8.348244 -0.675 = 7.673244
The deviation from linearity could be due to effect of D´ (?)In which case Dnju =
-22
-20
-18
-16
-14
-12
-10
-8
7654321
Coefficient values ± one standard deviation K0 = -3.3488 ± 0.475 K1 = -3.4892 ± 0.479 K2 = 0.87454 ± 0.135 K3 = -0.11082 ± 0.0111
-22
-20
-18
-16
-14
-12
-10
-8
8765432
Coefficient values ± one standard deviation K0 = 1.1258 ± 1.08 K1 = -5.5708 ± 0.778 K2 = 1.207 ± 0.168 K3 = -0.11082 ± 0.0111
-22
-20
-18
-16
-14
-12
-10
-8
9876543
Coefficient values ± one standard deviation K0 = 8.0145 ± 2.03 K1 = -8.3173 ± 1.14 K2 = 1.5395 ± 0.201 K3 = -0.11082 ± 0.0111
-22
-20
-18
-16
-14
-12
-10
-8
10987654
Coefficient values ± one standard deviation K0 = 17.982 ± 3.38 K1 = -11.729 ± 1.58 K2 = 1.872 ± 0.234 K3 = -0.11082 ± 0.0111
It is difficult to simulate the spectrum by using B´and D´parameters for theg state.Hence large perturbation / possibly another spectral system in that region