Teoria de Losas Hormigon

7/24/2019 Teoria de Losas Hormigon

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DETERMINACIÓN DEL ESPESOR DE LA LOSA MACIZA

h = =

h = 11,60 m

h = =

h = 12,95 m.

ASUMIMOS e ó h = 13 cm

DETERMINACION DEL TIPO DE LOSA

Para el presente caso.A = 5,18 m

B = 5,30 m

5,3 < 2*5,18

5,3 < 10,9 (Losa e !os !"#ecc"oes$.


B = 5,18 m

5,18 % 2*2,50

5,18 % 5 (Losa e &a !"#ecc"ó$.

Para el presente caso.

ANÁLISIS DE CARGAS

B < 2A (Losa e !os !"#ecc"oes$.

B % 2A (Losa e &a !"#ecc"ó$.

Se m&es'#a e )aos )as )osas 1 so e !os !"#ecc"oe

Se m&es'#a e )aos )as )osas 2 so e &a !"#ecc"ó.

+180

(2(518$2(530$$+180

+-0 518+-0



Análisis de cargas

Losa !aci"a.

=

=

eso #o"o 'a/"&e#"a =

eso #o"o ce#am"ca =

O'#as ca#as =

DISTRI#$CI%N DE CAR&AS EN LOS E'ES ()*+,.

a#a )osas e !os !"#ecc"oes se !e'a))a e )as s"&"ee'es o#m&)

593 +m

341 +m

Carga M-erta

eso #o"o )osa 0,13m * 2-52 +m3

eso #o"o ca#e'a !e "e)ac"ó 2100 +m3 * 0,03 m

eso #eo&e c"e)o #aso 1250 +m3 * 0,02m

7AA :O:AL MU;:A = 593,00 +m2.

7AA :O:AL IA = 341,00 +m2.

' =

>

L>

= 5,18 m

L

= 5,30 m

7AA :O:AL MU;:A = 593 +m2* 1m =

7AA :O:AL IA = 341 +m2* 1m =

>= 310 +m

qx = [ ? $@-$+( (( $@- $@-$( (

qy = [ ? $@-$+( (

( $@- $@-$( (

qx = [ ? $@-$+( (

( $@- $@-$( (

qx =[ (593?(5,30$@-$+((5,18$@-(5,30$@-$



Carga ia

Carga M-erta

= 283 +m

>= 19- +m

= 144 +m

L>

= 3,15 m

L

= 5,30 m

>= 524 +m

qy = [ ? $@-$+( (

( $@- $@-$( (

qy = [ (593?(5,18$@-$+((5,18$@-(5,30$@-$

qx = [ ? $@-$+( (

( $@- $@-$( (

qx = [ (341?(5,3$@-$+((5,18$@-(5,30$@-$

qy = [ ? $@-$+( (

( $@- $@-$( (

qy = [ (341?(5,18$@-$+((5,18$@-(5,30$@-$

qx = [ ? $@-$+( (( $@- $@-$( (

qx =[ (593?(5,30$@-$+((3,15$@-(5,30$@-$



Carga ia

Carga M-erta

= 66 +m

> = 330 +m

= -1 +m

L>

= 5,18 m

L

= -,48 m

> = 2-9 +m

qy = [ ? $@-$+( (( $@- $@-$( (

qy = [ (593?(3,15$@-$+((3,15$@-(5,30$@-$

qy = [ ? $@-$+( (

( $@- $@-$( (

qy =

[ (341?(3,15$@-$+((3,15$@-(5,30$@-$

qx = [ ? $@-$+( (

( $@- $@-$( (

qx = [ (341?(5,30$@-$+((3,15$@-(5,30$@-$

qx = [ ? $@-$+( (

( $@- $@-$( (

qx =[ (593?(-,48$@-$+((5,18$@-(-,48$@-$



Carga ia

Carga M-erta

= 3--+m

> = 1-8 +m

= 215 +m

L>

= 3,15 m

L

= 2,-3 m

> = 155 +m

qy = [ ? $@-$+( (( $@- $@-$( (

qy = [ (593?(5,18$@-$+((5,18$@-(-,48$@-$

qx = [ ? $@-$+( (

( $@- $@-$( (

qx = [ (341?(-,48$@-$+((5,30$@-(-,48$@-$

qy = [ ? $@-$+( (

( $@- $@-$( (

qy = [ (341?(5,18$@-$+((5,18$@-(-,48$@-$

qx = [ ? $@-$+( (

( $@- $@-$( (

qx =[ (593?(2,-3$@-$+((3,15$@-(2,-3$@-$



Carga ia

= -38 +m

> = 94 +m

= 24- +m

qy = [ ? $@-$+( (( $@- $@-$( (

qy = [ (593?(3,15$@-$+((3,15$@-(2,-3$@-$

qx = [ ? $@-$+( (

( $@- $@-$( (

qx = [ (341?(2,-3$@-$+((3,15$@-(2,-3$@-$

qy = [ ? $@-$+( (

( $@- $@-$( (

qy = [ (341?(3,15$@-$+((3,15$@-(2,-3$@-$



.



s

320 +m2

63 +m2

25 +m2

125 +m2

30 +m2

30 +m2

593 +m2











"a 13

DETERMINACIÓN DEL ESPESOR DE LA LOSA NERVADA

h = =

h = 18,60 m

h = =

h = 19,95 m.

ASUMUIMOS e ó h = 20 cm

DETERMINACION DEL TIPO DE LOSA


B = 5,30 m

5,3 < 2*5,18

5,3 < 10,9 (Losa e !os !"#ecc"oes$.


B = 5,18 m

5,18 % 2*2,50

5,18 % 5 (Losa e &a !"#ecc"ó$.

Para el presente caso.

ANÁLISIS DE CARGAS

B < 2A (Losa e !os !"#ecc"oes$.

B % 2A (Losa e &a !"#ecc"ó$.

Se m&es'#a e )aos )as )osas 1 so e !os !"#ecc"oes.

Se m&es'#a e )aos )as )osas 2 so e &a !"#ecc"ó.

+180

(2(518$2(530$$+1804

+-04

518+-04



"a 1-

Análisis de cargas

Losa nerada en 1 direcci/n.

=eso #o"o )osa (e#"o, )osa com)eme'o$ =

=

eso #o"o 'a/"&e#"a =

eso #o"o ce#am"ca =

O'#as ca#as =

Losa nerada en 2 direcciones.

=

eso #o"o )osa (e#"o, )osa com)eme'o$ =

=

eso #o"o 'a/"&e#"a =eso #o"o ce#am"ca =

O'#as ca#as =

Losa nerada en 1 direcci/n.

Losa nerada en 2 direcciones.

eso #o"o )osa 2-52 +m3 * 0,08m


eso #eo&e c"e)o #aso 1250 +m3 * 0,02m

7AA :O:AL MU;:A = 5-3,00 +m2.

7AA :O:AL IA = 341,00 +m2.

eso #o"o )osa 2-52 +m3 * 0,08m


eso #eo&e c"e)o #aso 1250 +m3 * 0,02m

7AA :O:AL MU;:A = 616,00 +m2.

7AA :O:AL IA = 341,00 +m2.

A :O:AL MU;:A = 5-3,00 +m2. *0,50 m

A :O:AL IA = 341,00 +m2. * 0,50 m

AA :O:AL MU;:A = 616,00 +m2. * 0,50 m

A :O:AL IA = 341,00 +m2. * 0,50 m



"a 15

DISTRI#$CI%N DE CAR&AS EN LOS E'ES ()*+,.

a#a )osas e !os !"#ecc"oes se !e'a))a e )as s"&"ee'es o#m&)a

308 +m

186 +m

Carga M-erta

Carga ia

' =

>

L>

= 5,18 m

L = 5,30 m

7AA :O:AL MU;:A =

7AA :O:AL IA =

>= 161 +m

= 1-4 +m

qx = [ ? $@-$+( (

( $@- $@-$( (

qy = [ ? $@-$+( (

( $@- $@-$( (

qx = [ ? $@-$+( (

( $@- $@-$( (

qx =

[ (308?(5,30$@-$+((5,18$@-(5,30$@-$

qy = [ ? $@-$+( (

( $@- $@-$( (

qy = [ (308?(5,18$@-$+((5,18$@-(5,30$@-$

qx = [ ? $@-$+( (

( $@- $@-$( (

qx = [ (186?(5,3$@-$+



"a 16

Carga M-erta

Carga ia

>= 94 +m

= 89 +m

L>

= 3,15 m

L

= 5,30 m

>= 24- +m

= 3- +m

> = 165 +m

((5,18$@-(5,30$@-$

qy = [ ? $@-$+( (

( $@- $@-$( (

qy = [ (186?(5,18$@-$+((5,18$@-(5,30$@-$

qx = [ ? $@-$+( (

( $@- $@-$( (

qx =[ (308?(5,30$@-$+((3,15$@-(5,30$@-$

qy = [ ? $@-$+( (

( $@- $@-$( (

qy = [ (308?(3,15$@-$+((3,15$@-(5,30$@-$

qx = [ ? $@-$+( (

( $@- $@-$( (

qx = [ (186?(5,30$@-$+((3,15$@-(5,30$@-$





"a 18

Carga M-erta

Carga ia

= 108 +m

L>

= 3,15 m

L

= 2,-3 m

> = 81 +m

= 224 +m

> = -9 +m

= 134 +m

qy = [ (186?(5,18$@-$+((5,18$@-(-,48$@-$

qx = [ ? $@-$+( (

( $@- $@-$( (

qx =[ (308?(2,-3$@-$+((3,15$@-(2,-3$@-$

qy = [ ? $@-$+( (

( $@- $@-$( (

qy = [ (308?(3,15$@-$+((3,15$@-(2,-3$@-$

qx = [ ? $@-$+( (

( $@- $@-$( (

qx = [ (186?(2,-3$@-$+((3,15$@-(2,-3$@-$

qy = [ ? $@-$+( (

( $@- $@-$( (

qy = [ (186?(3,15$@-$+((3,15$@-(2,-3$@-$



"a 19

ESTADOS DE CAR&A LOSA EN DIRECCI%N 0)0 TRAMOS 32

3,15 2,25 5,18

4 3 2 1

194,00 Kg-m

310,00 Kg-m

371,00 Kg-m

593,00 Kg-m

330,00 Kg-m

527,00 Kg-m

194,00 Kg-m

310,00 Kg-m593,00 Kg-m

330,00 Kg-m

527,00 Kg-m

310,00 Kg-m

371,00 Kg-m

593,00 Kg-m527,00 Kg-m

310,00 Kg-m

371,00 Kg-m

593,00 Kg-m

330,00 Kg-m

527,00 Kg-m

194,00 Kg-m

310,00 Kg-m

371,00 Kg-m

593,00 Kg-m527,00 Kg-m

Mmax= -860,57 Kg-m

Mmax= -699,48 Kg-mMmax= -1282,34 Kg-m

Mmax= 812,41 Kg-m

Mmax= 1134,35 Kg-m

Mmax= -1295,11 Kg-m

Mmax= 24,10 Kg-m



"a 20



"a 21

242 +m

186 +m

308 +m

186 +m

196,16 +m3

43,6 +m2

63 +m2

25 +m2

125 +m2

30 +m2

30 +m2

5-3 +m2

196,16 +m3

1-4,12 +m2

63 +m2

25 +m2

125 +m2

30 +m2

30 +m2

616,28 +m2



"a 22

s



"a 23



"a 2-



"a 25



1

1

95,11 Kg-m

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Teoria de Losas Hormigon