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Beer 5a ediçãoExercício 2.16
δ=Σδ=P⋅50,8mm
200kN
mm22026,8mm2
+P⋅25,4mm
200kN
mm2506,7mm2
=5,012⋅10−4 P=0,0508mm
P=0,0508
5,012⋅10−4P=101,34 kN